High roller holdem
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Below we've listed all odds and probabilities mentioned in this article. With kings it's possible, but unlikely, to run into a better hand pre-flop. Three players at a 6-max-table are dealt and pair and all three flop a set. The odds for that to happen are 1 in This is a scoring system that was a collaborative effort and completed on my own time with differentiated scoring.
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Set over set over set? Hitting the bad beat jackpot? If you've played poker live or online for any stretch of time - even a very, very short amount of time - you've seen hands play out you never thought possible. One-outers on the river to crush your massive favorite. Below we've compiled a comprehensive list of unusual long-shot odds for Texas Hold'em — numbers and percentages to impress or possibly annoy your fellow players at the table.
And, importantly, to unmask ruthless exaggerators who claim the most unlikely things happened to them just the other day. There are 1, different hole-card combinations in Texas Hold'em and 6 of them are aces. Thus the odds of being dealt aces in any hand are 6 to 1, or 1 to or 0. You probably already knew that.
But what are the odds that one of your opponents is dealt aces as well? With aces you have nothing to fear before the flop. But with pocket kings there is always this nagging thought in the back of your head that maybe, just maybe, one of your opponents has aces.
If you're playing heads-up you're only up against one opponent. That opponent only has aces roughly once every hands. But at a full-ring table 9 players with 8 opponents, it's suddenly much more likely — albeit still a long-shot — that someone has aces against your kings. The odds for that to happen are 1 in You're almost always better off disregarding this worst-case scenario, but sometimes really good players can make impressive folds with kings before the flop.
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Join Stack Overflow to learn, share knowledge, and build your career. I've implemented a Texas Hold'em game using C. I wrote classes like Card, Deck, Player, Table etc My question is how should I pick the best hand combination if I got 7 cards 2 hand, 5 from the table. Then runs backwards from highest ranking hand to lowest. If one of these methods returns true, then you can easily pick off the best hand that satisfies that condition. Start by sorting the cards, it will make doing your search for the best hand that much easier, then you just have to compare adjacent elements for multiples of the same number, or straights.
The easiest way to do it is make every collection of 5 cards possible and grab the hand value. Remember the best hand. There are only 21 combinations for the 7 card situation, so it's not good in terms of optimality, but it's not terrible either unless you are using this for research. Alternatively you could create an array that has 1 entry for each card, and each index is a pointer to new array which has all 2 card combinations, and each index in that is an array for all 3 card combinations, etc.
If you work it out with all suit and rank abstractions possible, the total size of the data structure is about MB in memory. Don't do it like this, it is awfully slow and actually rather cumbersome to write the logic is quite hairy. Also, for Monte Carlo simulations where you'll need to run hundred of millions of hands, such an approach simply cannot stand.
See this link for a survey of available techniques. Actually, using table-based comparison algorithms is much simpler to code than using a truckload of if statements. Most of the routines presented in the above article are available in already-bundled C libraries that you can plug your code into. Then, foreach additional card, find the lowest in the card hand, and see if the extra card is larger, if so, switch them.